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	<title>Comments on: How many amps would a device use per hour from a 12 V battery?</title>
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	<description>Subwoofer drivers</description>
	<pubDate>Fri, 10 Feb 2012 15:43:35 +0000</pubDate>
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		<title>By: ►BobB◄</title>
		<link>http://www.acoupower.com/amps/how-many-amps-would-a-device-use-per-hour-from-a-12-v-battery/comment-page-1#comment-7664</link>
		<dc:creator>►BobB◄</dc:creator>
		<pubDate>Sun, 27 Sep 2009 11:46:59 +0000</pubDate>
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		<description>it will not power the drill.

First, the &#34;600W&#34; inverter is 600W PEAK not average power. Average is about 300W, and the drill will cause the inverter to shut down.

To find the current (AMPS), use Ohm's law;
Power equals Voltage times Current

               P
____________________
                &#124;
       I        &#124;        E

500W/240V = ~2A
Your drill pulls about 2Amps&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;yahoo would not allow me to format the formula tree correctly.</description>
		<content:encoded><![CDATA[<p>it will not power the drill.</p>
<p>First, the &quot;600W&quot; inverter is 600W PEAK not average power. Average is about 300W, and the drill will cause the inverter to shut down.</p>
<p>To find the current (AMPS), use Ohm&#8217;s law;<br />
Power equals Voltage times Current</p>
<p>               P<br />
____________________<br />
                |<br />
       I        |        E</p>
<p>500W/240V = ~2A<br />
Your drill pulls about 2Amps<br /><b>References : </b><br />yahoo would not allow me to format the formula tree correctly.</p>
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