How is you can have higher amps then volts?
It seems counter-intuitive to have a flow geater then your pressure. I always assumed that when you make a super conductor your volts would equal your amps as you have 0 resistance. But from what I calculated the only way to get higher amps then volts is to have fractional resistance which doesnt make much sence to me.
You can have small resistance. Take a small piece of metal wire, for example. It has a resistance of less than one ohm. If you can maintain 1 Volt across that, you will get more than 1 Amp (using Ohm’s law, V = I*R). Although doing this requires a power supply capable of supplying that much current (i.e. if you used a simple 1.5 V battery, its internal resistance will add to the overall resistance and you will not get much current).
Anyways having a "flow" greater than your "pressure" doesn’t mean anything. It’s like saying my "weight" is greater than your "height".
Think about it.
If you were to put a short circuit across any ideal voltage source the current would approach infinity.
In practice a voltage source always has some finite source resistance that limits the current.
Now consider connecting a long piece of wire that has a finite resistance say 0.1 ohms across the source. A source of 10 volts would result in a current of 10/0.1 or 100 A.
Why is that a problem?
References :
You can have small resistance. Take a small piece of metal wire, for example. It has a resistance of less than one ohm. If you can maintain 1 Volt across that, you will get more than 1 Amp (using Ohm’s law, V = I*R). Although doing this requires a power supply capable of supplying that much current (i.e. if you used a simple 1.5 V battery, its internal resistance will add to the overall resistance and you will not get much current).
Anyways having a "flow" greater than your "pressure" doesn’t mean anything. It’s like saying my "weight" is greater than your "height".
References :